# Universal Chord Theorem. Suppose $f:[0,1]\to \mathbf R$ is a continuous function, where $f(0) = f(1)$. Then, for each positive integer $n$, there exists $x \in [0,1]$ such that $f(x) = f(x + 1/n)$. Suppose `f:[0,1]-> bb "R"` is a continuous function, where `f(0)=f(1)`. Then, for each positive integer `n`, there exists `x \in [0,1]` such that `f(x) = f(x + 1 / n)`.